Đáp án đúng: A
1,3.
Cr không tan trong kiềm loãng .
$\displaystyle {{n}_{KOH}}=0,3\,\,mol\,\,\xrightarrow{BTNT.K}\,\,\,\,{{n}_{KAl{{O}_{2}}}}=0,3\,mol\to {{n}_{Al}}=0,3\,mol$
$\displaystyle \to 23,3g\left\{ \begin{array}{l}{{n}_{Al}}=0,3\,mol\\{{n}_{C{{r}_{2}}{{O}_{3}}}}=0,1\,mol\end{array} \right.\xrightarrow{BTNT.\text{Ox}i}X\left\{ \begin{array}{l}{{n}_{A{{l}_{2}}{{O}_{3}}}}=0,1\,mol\\{{n}_{Al}}=0,1\,mol\\{{n}_{Cr}}=0,2\,mol\end{array} \right.$
$\displaystyle \xrightarrow{BTNT}\left\{ \begin{array}{l}{{n}_{AlC{{l}_{3}}}}=0,3\,mol\\{{n}_{CrC{{l}_{2}}}}=0,2\,mol\end{array} \right.\xrightarrow{BTNT.Clo}a=1,3\,mol$