Phân tích các đa thức sau thành nhân tử:
a) \(5{{x}^{2}}y-10x{{y}^{2}} \)
b) \(3 \left( x+3 \right){{x}^{2}}+9 \)
c) \({{x}^{2}}{{y}^{2}}+xz-yz \)
A.\(a, 5xy\left( {x-2y} \right)\)
\(b, \left( {x -3} \right)\left( {6+x} \right)\)
\(c, \left( {x-y} \right)\left( {x + y-z} \right)\)
B.\(a, 5xy\left( {x-2y} \right)\)
\(b, \left( {x + 3} \right)\left( {6-x} \right)\)
\(c, \left( {x-y} \right)\left( {x + y-z} \right)\)
C.\(a, 5xy\left( {x-2y} \right)\)
\(b, \left( {x + 3} \right)\left( {6-x} \right)\)
\(c, \left( {x+y} \right)\left( {x + y+z} \right)\)
D.\(a, 5xy\left( {x+2y} \right)\)
\(b, \left( {x + 3} \right)\left( {6-x} \right)\)
\(c, \left( {x-y} \right)\left( {x + y-z} \right)\)
a) \(5{{x}^{2}}y-10x{{y}^{2}} \)
b) \(3 \left( x+3 \right){{x}^{2}}+9 \)
c) \({{x}^{2}}{{y}^{2}}+xz-yz \)
A.\(a, 5xy\left( {x-2y} \right)\)
\(b, \left( {x -3} \right)\left( {6+x} \right)\)
\(c, \left( {x-y} \right)\left( {x + y-z} \right)\)
B.\(a, 5xy\left( {x-2y} \right)\)
\(b, \left( {x + 3} \right)\left( {6-x} \right)\)
\(c, \left( {x-y} \right)\left( {x + y-z} \right)\)
C.\(a, 5xy\left( {x-2y} \right)\)
\(b, \left( {x + 3} \right)\left( {6-x} \right)\)
\(c, \left( {x+y} \right)\left( {x + y+z} \right)\)
D.\(a, 5xy\left( {x+2y} \right)\)
\(b, \left( {x + 3} \right)\left( {6-x} \right)\)
\(c, \left( {x-y} \right)\left( {x + y-z} \right)\)
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