Đáp án:
$6{x^3}.{y^2}\left( {2 - x} \right) + 9{x^2}.{y^2}\left( {x - 2} \right) = 3{x^2}.{y^2}\left( {x - 2} \right).\left( { - 2x + 3} \right)$
Giải thích các bước giải:
Ta có:
$\begin{array}{l}
6{x^3}.{y^2}\left( {2 - x} \right) + 9{x^2}.{y^2}\left( {x - 2} \right)\\
= \left( { - 6{x^3}.{y^2}} \right)\left( {x - 2} \right) + 9{x^2}.{y^2}\left( {x - 2} \right)\\
= 3{x^2}.{y^2}\left( {x - 2} \right).\left( { - 2x + 3} \right)
\end{array}$
Vậy $6{x^3}.{y^2}\left( {2 - x} \right) + 9{x^2}.{y^2}\left( {x - 2} \right) = 3{x^2}.{y^2}\left( {x - 2} \right).\left( { - 2x + 3} \right)$
