Giải thích các bước giải:
\(\begin{array}{l}
1.\left[ \begin{array}{l}
7 - x = 0\\
x - 4 = 0\\
x + 4 = 0
\end{array} \right. \to \left[ \begin{array}{l}
x = 7\\
x = 4\\
x = - 4
\end{array} \right.\\
3.4{x^2} + {x^2} - 2x + 1 - 4{x^2} - 4x - 1 = 0\\
\to {x^2} - 6x = 0\\
\to \left[ \begin{array}{l}
x = 0\\
x = 6
\end{array} \right.\\
5.{x^4} + {x^2} - 2 = 0\\
\to \left[ \begin{array}{l}
{x^2} = 1\\
{x^2} = - 2\left( l \right)
\end{array} \right. \to \left[ \begin{array}{l}
x = 1\\
x = - 1
\end{array} \right.\\
6.{x^4} - 8{x^3} - 9{x^2} = 0\\
\to \left[ \begin{array}{l}
{x^2} = 0\\
{x^2} - 8x - 9 = 0
\end{array} \right.\\
\to \left[ \begin{array}{l}
x = 0\\
x = 9\\
x = - 1
\end{array} \right.\\
7.16{x^2} - 40x + 25 + 28x - 35 - 8 = 0\\
\to \left( {2x - 3} \right)\left( {4x + 3} \right) = 0\\
\to \left[ \begin{array}{l}
x = \frac{3}{2}\\
x = - \frac{3}{4}
\end{array} \right.
\end{array}\)