$3^{(2x + 1)} - 28.3^x + 9 = 0$
$⇔ 3.(3^x)² - 28.3^x + 9 = 0$
$⇔ (3.3^x - 1).(3^x - 9) = 0$
$⇔\left \{ {{3.3^x - 1 = 0} \atop {3^x - 9 = 0}} \right.$
$⇔\left \{ {{3^x = 1/3 = 3^{(- 1)}} \atop {3^x = 9 = 3^2}} \right.$
$⇔\left \{ {{x1 = x = - 1} \atop {x2 = x = 2}} \right.$
$T = x1 - 2x2 = - 1 - 2.2 = - 5$