A.relaxB.enterC.behaveD.allow
A.separatedB.removedC.dividedD.disagreed
A.\(m = \dfrac{{3\sqrt 2 - 2}}{4}\)B.\(m = \dfrac{{\sqrt 2 + 2}}{4}\)C.\(m = \dfrac{{3\sqrt 2 - 4}}{4}\)D.\(m = \dfrac{{\sqrt 2 + 4}}{4}\)
A.\(y = x + 1\) và \(y = \dfrac{1}{4}x + \dfrac{1}{2}\).B.\(y = x + 1\) và \(y = \dfrac{1}{4}x - \dfrac{1}{2}\).C.\(y = x - 1\) và \(y = \dfrac{1}{4}x - \dfrac{1}{2}\).D.\(y = x - 1\) và \(y = \dfrac{1}{4}x + \dfrac{1}{2}\).
A.\(m = 0;m = - 2\)B.\(m = 0;m = - 4\)C.\(m = 0;m = - 6\)D.\(m = 0;m = - 1\)
A.\(x = 1 + \sqrt 3 \)B.\(x = 1 \pm \sqrt 3 \)C.\(x = 1 - \sqrt 3 \)D.\(x = 1 \pm \sqrt 2 \)
A.\(\left( {x;y} \right) \in \left\{ {\left( { - \sqrt 2 ;4} \right);\left( {\sqrt 2 ;4} \right);\left( {0;1} \right);\left( {1;3} \right)} \right\}\)B.\(\left( {x;y} \right) \in \left\{ {\left( { - \sqrt 2 ;4} \right);\left( {\sqrt 2 ;4} \right);\left( {0;1} \right);\left( { - 1;3} \right)} \right\}\)C.\(\left( {x;y} \right) \in \left\{ {\left( { - \sqrt 2 ;4} \right);\left( {\sqrt 2 ;4} \right);\left( {0;2} \right);\left( {1;3} \right)} \right\}\)D.\(\left( {x;y} \right) \in \left\{ {\left( { - \sqrt 2 ;4} \right);\left( {\sqrt 2 ;4} \right);\left( {0;2} \right);\left( { - 1;3} \right)} \right\}\)
A.B.C.D.
A.\(\dfrac{{\sqrt 2 }}{4}{\left( {\dfrac{{2a}}{{2 + \sqrt {2 - \sqrt 2 } }}} \right)^2}\)B.\(\dfrac{{\sqrt 2 }}{4}{\left( {\dfrac{{2a}}{{2 + \sqrt {2 + \sqrt 2 } }}} \right)^2}\)C.\(\dfrac{{\sqrt 2 }}{4}{\left( {\dfrac{{2a}}{{2 - \sqrt {2 - \sqrt 2 } }}} \right)^2}\)D.\(\dfrac{{\sqrt 2 }}{4}{\left( {\dfrac{{2a}}{{2 - \sqrt {2 + \sqrt 2 } }}} \right)^2}\)
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