Đáp án:
1) = -2x3 - 13x2 - x - 12
2) = -5x3 - 38x2 - 76x - 46
Giải thích các bước giải:
$1) -3x(x+2$)$^{2}$ $+ ( x+3)(x-1)(x+1)-(2x-$ $3)^{2}$
$= -3x($$x^{2}$ $+4x + 4)+(x+3)($ $x^{2}$ $- 1)($$4x^{2}$ $-12x + 9)$
$= $ $-3x^{3}$ $-$ $12x^{2}$ $-$ $12x$ $+x^{3}$$+$ $3x^{2}$ $-x -3 -$ $4x^{2}$ $+12-9$
$=($ $-3x^{3}$ $+x^{3}$) $+($ $-12x^{2}$ $+$ $3x^{2}$ $-$ $4x^{2}$) $+$ $(-12x - x + 12x)$ $+(-3-9)$
$-2x^{3}$ $-13x^{2}$ $-x-12$
$2) (x-3)(x+3)(x+2)$ $-(x-1)($ $x^{2}$ $- 3)-5x(x$ $-5)^{2}$
$= $ $(x^{2} -9)(x+2)-$ $(x^{3}-$ $x^{2}-3x+3)-5x($ $x^{2}+8x+16)-($ $x^{2}-10x+25)$
= x3 + 2x2 - 9x - 18 - x3 + x2 + 3x - 3 - 5x3 - 40x2 - 80x - x2 + 10x - 25
$=(x^{3}-$ $x^{3}-$ $5x^{3}) + ($ $2x^{2}+$ $x^{2}-$ $40x^{2}-$ $x^{2})+(-9x + 3x-80x+10x)+(-18 -3-25)$
$=$ $-5x^{3}-$ $38x^{2}-76x-46$