1) (2a-b+c) +(b-c+a) +(c-2a+b)
=2a-b+c+b-c+a+c-2a+b
= (2a-2a)+(b-b) +(c-c) + (a+b+c)
= 0+0+0+(a+b+c)
=a+b+c
2)(a-b+c) +(b-c-a) -a-b-c
=a-b+c+b-c-a-a-b-c
=(a-a) +(b-b) +(c-c) -a-b-c
=0+0+0-a-b-c
=-(a+b+c)
3)(a+b+c). (a+b+c)-2.(a. b+b. c+c. a)
câu 3 mình chưa nghĩ ra