Rút gọn : $C=\left( {{a}^{\frac{2}{3}}}+1 \right)\left( {{a}^{\frac{4}{9}}}+{{a}^{\frac{2}{9}}}+1 \right)\left( {{a}^{\frac{2}{9}}}-1 \right)$ ta được
A. ${{a}^{\frac{1}{3}}}+1$
B. ${{a}^{\frac{4}{3}}}+1$
C. ${{a}^{\frac{4}{3}}}-1$
D. ${{a}^{\frac{1}{3}}}-1$