S = 4 + $4^{2}$ + $4^{3}$ +....+ $4^{19}$
S = $4^{1}$ + $4^{2}$ + $4^{3}$ + .... + $4^{19}$
4.S = 4 . ( $4^{1}$ + $4^{2}$ + $4^{3}$ + .... + $4^{19}$ )
4.S = $4^{2}$ + $4^{3}$ +....+ $4^{20}$
4.S - S = ( $4^{2}$ + $4^{3}$ +....+ $4^{20}$ ) - ( 4 + $4^{2}$ + $4^{3}$ +....+ $4^{19}$ )
3.S = $4^{20}$ - 4
=> S = $\frac{$4^{20}$ - 4}{3}$
Tìm số tự nhiên n để 3.S + 4 = 4 mũ n ( mik chịu, sorry )
~ xin ctlhn ~