Giải thích các bước giải :
`↓↓↓`
`(2x+1)(3y−2)=−55`
Suy ra :
`(2x+1) ; (3y-2) ∈ Ư(-55) = { ±1 ; ±5 ; ±11 ; ±55 }`
Ta có bảng giá trị sau :
\begin{array}{|c|c|}\hline \text{2x + 1}&\text{1}&\text{-1}&\text{5}&\text{-5}&\text{11}&\text{-11}&\text{55}&\text{-55}\\\hline 3y - 2&\text{-55}&\text{55}&\text{-11}&\text{11}&\text{-5}&\text{5}&\text{-1}&\text{1}\\\hline x&\text{0}&\text{-1}&\text{2}&\text{-3}&\text{5}&\text{-6}&\text{27}&\text{-28}\\\hline y&\text{X}&\text{19}&\text{-3}&\text{X}&\text{-1}&\text{X}&\text{X}&\text{1}\\\hline \end{array}
Vậy `....`
