A = $\frac{2021^{2021}+2}{2021^{2021}-1}$ = $\frac{2021^{2021}-1}{2021^{2021}-1}$ + $\frac{3}{2021^{2021}-1}$ = 1 + $\frac{3}{2021^{2021}-1}$
B = $\frac{2021^{2021}}{2021^{2021}-3}$ = $\frac{2021^{2021}-3}{2021^{2021}-3}$ + $\frac{3}{2021^{2021}-3}$= 1 + $\frac{3}{2021^{2021}-3}$
Vì -1 > -3
⇒ 2021$^{2021}$ - 1 > 2021$^{2021}$ - 3
⇒ $\frac{1}{2021^{2021}-1}$ < $\frac{1}{2021^{2021}-3}$
⇒ $\frac{3}{2021^{2021}-1}$ < $\frac{3}{2021^{2021}-3}$
⇒ 1 + $\frac{3}{2021^{2021}-1}$ < 1 + $\frac{3}{2021^{2021}-3}$
⇒ A < B
Chúc bn học tốt!
Giải thích các bước giải:
