`A = \overline{a42} + \overline{5b2} + \overline{24c}`
`A = \overline{a00} + 40 + 2 + 500 + \overline{b0} + 2 + 200 + 40 + c`
`A = ( \overline{a00} + \overline{b0} + c ) + ( 40 + 2 + 500 + 2 + 200 + 40 )`
`A = \overline{abc} + 784`
Vì ` \overline{abc} + 784 > \overline{abc} + 573 => A > B`
`#dtkc`