Ta có:
$\frac{2018}{2019}>$ $\frac{2018}{2019+2020+...+2029}$
$\frac{2019}{2020}>$ $\frac{2019}{2019+2020+...+2029}$
$...$
$\frac{2028}{2029}>$ $\frac{2028}{2019+2020+...+2029}$
Cộng vế ta được:
$\frac{2018}{2019}+$$\frac{2019}{2020}+...+$ $\frac{2028}{2029}>$$\frac{2018+2019+...+2028}{2019+2020+...+2029}$
Vậy $A>B$