Ta có: $\dfrac{c}{d}=\dfrac{c(b+f)}{d(b+f)}=\dfrac{bc+cf}{bd+df}(1)$
$\dfrac{a+e}{b+f}=\dfrac{d(a+e)}{d(b+f)}=\dfrac{ad+de}{bd+df}(2)$
Mặt khác: `ad-bc=2` ; `cf-de=2`
`->ad-bc=cf-de=2`
`->ad-bc=cf-de`
`->ad+de=cf+bc`
`->`$\dfrac{ad+de}{bd+df}=\dfrac{cf+bc}{bd+df}(3)$
Từ `(1)(2)(3)->` $\dfrac{c}{d}=\dfrac{a+e}{b+f}$
Chúc bạn học tốt !!!!!!!