Đáp án:
Giải thích các bước giải:
$a,2\sqrt{5}=\sqrt{20}$
$\sqrt{20}>\sqrt{7}⇒2\sqrt{5}>\sqrt{7}$
$b,5\sqrt{2}=\sqrt{50}$
$2\sqrt{3}=\sqrt{12}$
$\sqrt{50}>\sqrt{12}⇒5\sqrt{2}>2\sqrt{3}$
$c,5=\sqrt{25}$
$2\sqrt{6}=\sqrt{24}$
$\sqrt{25}>\sqrt{24}⇒5>2\sqrt{6}$
$d,-3\sqrt{2}=-\sqrt{9}.\sqrt{2}=-\sqrt{18}$
$-2\sqrt{3}=-\sqrt{12}$
$\sqrt{18}>\sqrt{12}⇒-\sqrt{18}<-\sqrt{12}⇒-3\sqrt{2}<-2\sqrt{3}$