(Tách để tìm GTLN?)
$-3m^2+2m+32= -(3m^2-2m-32)= -[(\sqrt{3}m)^2 - 2.\sqrt{3}m.\dfrac{1}{\sqrt{3}} + \dfrac{1}{3} - \dfrac{97}{3}]$
$= -(\sqrt{3}m-\dfrac{1}{\sqrt{3}})^2+\dfrac{97}{3}\le \dfrac{97}{3}$
$max=\dfrac{97}{3}\Leftrightarrow m=\dfrac{1}{3}$
