Đáp án:
d) Bậc 11
Giải thích các bước giải:
\(\begin{array}{l}
a)A = \dfrac{5}{4}{x^2}y.\left( { - \dfrac{5}{6}} \right)xy.\left( {\dfrac{7}{3}} \right)xy\\
= - \dfrac{{175}}{{72}}{x^4}{y^3}\\
\to Bậc:4 + 3 = 7\\
b)B = \dfrac{1}{2}x.\dfrac{1}{4}{x^2}.\dfrac{1}{8}{x^3}.2.4.8.{y^6}\\
= {x^6}{y^6}\\
\to Bậc:6 + 6 = 12\\
c)C = 2{x^2}{y^3}{z^4}.\left( { - \dfrac{1}{2}x{y^2}} \right)\\
= - {x^3}{y^5}{z^4}\\
\to Bậc:3 + 5 + 4 = 12\\
d)D = \dfrac{{{a^2}}}{4}.3xy.4{a^2}{x^3}.{\left( {\dfrac{{13}}{3}a{y^2}} \right)^3}\\
= 3{a^4}{x^4}y.\dfrac{{2197}}{{27}}.{a^3}{y^6}\\
= \dfrac{{2197}}{9}{a^7}{x^4}{y^7}\\
\to Bậc:4 + 7 = 11
\end{array}\)