Đáp án:
`(1 - 2x)^3 + 2x(2x - 1)(2x + 1) - 3(3 - 2x)^2 = 2`
`⇔ 1^3 - 3.1^2 .2x + 3.1.(2x)^2 - (2x)^3 + 2x[(2x)^2 - 1^2] - 3[3^2 - 2.3.2x + (2x)^2] = 2`
`⇔ 1 - 6x + 12x^2 - 8x^3 + 2x(4x^2 - 1) - 3(9 - 12x + 4x^2) = 2`
`⇔ 1 - 6x + 12x^2 - 8x^3 + 8x^3 - 2x - 27 + 36x - 12x^2 - 2 = 0`
`⇔ 28x - 28 = 0`
`⇔ 28x = 28`
`⇒ x = 28 : 28`
`⇒ x = 1`
Vậy `x =1`