Đáp án:
\(\left[ \begin{array}{l}
x = 6\\
x = 2
\end{array} \right.\)
Giải thích các bước giải:
\(\begin{array}{l}
\left| {x - 3} \right| + \left| {x - 5} \right| = 4\\
\to \left[ \begin{array}{l}
x - 3 + x - 5 = 4\left( {DK:x \ge 5} \right)\\
x - 3 - x + 5 = 4\left( {DK:5 > x \ge 3} \right)\\
- x + 3 - x + 5 = 4\left( {DK:x < 3} \right)
\end{array} \right.\\
\to \left[ \begin{array}{l}
2x = 12\\
2 = 4\left( l \right)\\
- 2x = - 4
\end{array} \right.\\
\to \left[ \begin{array}{l}
x = 6\\
x = 2
\end{array} \right.\left( {TM} \right)
\end{array}\)
