*) \(4x^2-4x=-1\Leftrightarrow4x^2-4x+1=0\Leftrightarrow\left(2x-1\right)^2=0\)

\(\Leftrightarrow2x-1=0\Leftrightarrow2x=1\Leftrightarrow x=\dfrac{1}{2}\) vậy \(x=\dfrac{1}{2}\)

*)\(8x^3+12x^2+6x+1=0\Leftrightarrow8x^3+8x^2+2x+4x^2+4x+1\)

\(\Leftrightarrow2x\left(4x^2+4x+1\right)+\left(x^2+4x+1\right)=0\Leftrightarrow\left(2x+1\right)\left(4x^2+4x+1\right)=0\)

\(\Leftrightarrow\left(2x+1\right)\left(2x+1\right)^2=0\Leftrightarrow\left(2x+1\right)^3=0\Leftrightarrow2x+1=0\)

\(\Leftrightarrow2x=-1\Leftrightarrow x=\dfrac{-1}{2}\) vậy \(x=\dfrac{-1}{2}\)

a) x+5x2=0

=>x(1+5x)=0

=>x=0 hoặc 1+5x=0 =>x=\(\dfrac{1}{5}\)

b)x+1=(x+1)2

=>(x+1)-(x+1)2=0

=>(x+1)(1-x-1)=0

=>-x(x+1)=0

=>\(\left[{}\begin{matrix}-x=0\Rightarrow x=0\\x+1=0\Rightarrow x=-1\end{matrix}\right.\)

x2- 2x +1=4

- giúp em vsss

\(x^2-2x+1=4\) \(\left(x-1\right)^2=2^2\) \(\left(x-1\right)^2-2^{^{ }2}=0\) \(\left(x-3\right)\left(x-1\right)=0\) \(\Rightarrow x=3;x=1\)