$\text{*Ta có:(x-5).(x+5)-x.(x-3)=-10}$
`=>`$\text{}$$x^{2}-$ $5^{2}-$ $x^{2}+3x=-10$
$\Rightarrow$$\text{}$$x^{2}-25-$ $x^{2}+3x=-10$
$\Rightarrow$$\text{-25+3x=-10}$
$\Rightarrow$`\text{3x=-10-(-25)}`
$\Rightarrow$`\text{3x=15}`
$\Rightarrow$`\text{x=15:3}`
$\Rightarrow$`\text{x=5}`
`\text{Kl:Vậy:x=5}`
`\text{#Trang}`