$2x.\dfrac{1}{3}=3.(x+\dfrac{1}{5})-(-1)$
$2x.\dfrac{1}{3}=3x+\dfrac{3}{5}+1$
$\dfrac{2x}{3}-3x-\dfrac{8}{5}=0$
$x.\dfrac{2}{3}-3x=\dfrac{8}{5}$
$x.(\dfrac{2}{3}-3)=\dfrac{8}{5}$
$x.(-\dfrac{7}{3})=\dfrac{8}{5}$
$x=\dfrac{8}{5}:(-\dfrac{7}{3})$
$x=\dfrac{8}{5}.(-\dfrac{3}{7})$
$→x=-\dfrac{24}{35}$