Giải thích các bước giải:
`1)`
`2x^2 - 3x - 2 = 0`
`⇔ 2x^2 + x - 4x - 2 = 0`
`⇔ x(2x + 1) - 2(2x + 1) = 0`
`⇔ (x - 2)(2x + 1) = 0`
`⇔ x = 2 hoặc x = -1/2`
`Vậy S = {2; -1/2}`
Giải :
2x²-3x-2=0
⇔2x²+x-4x-2=0
⇔x(2x+1)-2(2x+1)=0
⇔(x-2)(2x+1)=0
⇔x-2=0 hoặc 2x+1=0
⇔x=2 hoặc x=`-1/2`
Tìm a,b,c,d $\begin{cases} d=10\\a+b+c+d=12\\8a+4b+2c+d=4\\27a+9b+3c+d=1 \end{cases}$
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