\(\left(x-\dfrac{1}{3}\right)^2-\dfrac{1}{4}=0\)
\(\Leftrightarrow\left(x-\dfrac{1}{3}\right)^2=\dfrac{1}{4}\)
\(\Leftrightarrow\left(x-\dfrac{1}{3}\right)^2=\left(\pm\dfrac{1}{2}\right)^2\)
\(\Leftrightarrow\left[{}\begin{matrix}x-\dfrac{1}{3}=\dfrac{1}{2}\\x-\dfrac{1}{3}=-\dfrac{1}{2}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{5}{6}\\x=\dfrac{-1}{6}\end{matrix}\right.\)
Vậy...
tik mik nha !!!
