Đáp án:
Giải thích các bước giải:
1)
$ (x + 3)^2 - (x - 2)(x + 2) = 4x + 17$
$=>x^2 + 6x + 9 - (x^2 - 4) - 4x = 17$
$=>(x^2 - x^2) + (6x - 4x) + (9 + 4) = 17$
$=> 2x + 13 = 17$
$=> 2x = 4$
$=> x = 2$
$ Vậy x = 2$
2)
$ (2x + 1)^2 - (4x - 1)(x - 3) - 15 = 0$
$=> 4x^2 + 4x + 1 - (4x^2 - 12x - x + 3) - 15 = 0$
$=> (4x^2 - 4x^2) + (4x + 12x + x) + (1 - 3 - 15) = 0$
$=> 17x - 17 = 0$
$=> 17x = 17$
$=> x = 1$
$ Vậy x = 1$
3)
$ (2x + 3)(x - 1) + (2x - 3)(1 - x) = 0$
$=> (2x + 3)(x - 1) - (2x - 3)(x - 1) = 0$
$=> (2x + 3 - 2x + 3)(x - 1) = 0$
$=> 6(x - 1) = 0$
$=> x - 1 = 0 $
$=> x = 1$
$ Vậy x = 1$
