\(x+15\%x=\left[\left(1,09-0,29\right).1\frac{1}{4}\right]:\left[\left(18,9-16\frac{13}{20}\right).\frac{8}{9}\right]\)
\(x+15\%x=\left[0,8.1\frac{1}{4}\right]:\left[2,25.\frac{8}{9}\right]\)
\(x+15\%x=1:2\)
\(x+15\%x=\frac{1}{2}\)
\(x+15x=\frac{1}{2}\)
\(16x=\frac{1}{2}\)
\(x=\frac{1}{2}:16=\frac{1}{32}\)
Vậy x=1/32