\(2\cdot\left|x-3\right|=4\)
\(\Rightarrow\left|x-3\right|=2\)
\(\Rightarrow\left[{}\begin{matrix}x-3=2\\x-3=-2\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=2+3\\x=-2+3\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=5\\x=1\end{matrix}\right.\)
Vậy \(x_1=1;x_5=5\)