$\frac{7}{2}$-|2x-$\frac{3}{4}$|=$\frac{-7}{4}$
|2x-$\frac{3}{4}$| =$\frac{7}{2}$- $\frac{-7}{4}$
|2x-$\frac{3}{4}$| =$\frac{7}{2}$+ $\frac{7}{4}$
|2x-$\frac{3}{4}$| =$\frac{14}{4}$+ $\frac{7}{4}$
|2x-$\frac{3}{4}$| =$\frac{21}{4}$
⇒2x-$\frac{3}{4}$=$\frac{-21}{4}$ hoặc 2x-$\frac{3}{4}$=$\frac{21}{4}$
+)2x-$\frac{3}{4}$=$\frac{-21}{4}$
2x =$\frac{-21}{4}$+$\frac{3}{4}$
2x =$\frac{-18}{4}$
x =$\frac{-18}{4}$:2
x =$\frac{-9}{4}$
+)2x-$\frac{3}{4}$=$\frac{21}{4}$
2x =$\frac{21}{4}$+$\frac{3}{4}$
2x =$\frac{24}{4}$
2x =6
x =6:2
x =3
Vậy x∈{$\frac{-9}{4}$;3}
