a)$\frac{2}{3}x$ - $\frac{4}{9}$ =$\frac{2}{9}$
$\frac{2}{3}x$ = $\frac{2}{9}$ +$\frac{4}{9}$
$\frac{2}{3}x$ = $\frac{2}{3}$
$x$ =$\frac{2}{3}: $\frac{2}{3}$
$x$ =1
b) ($4,5-2x$).$\frac{-14}{7} =$\frac{11}{14}$
$4,5-2x$ = $\frac{11}{14}$ : $\frac{-14}{7}$
$ \frac{9}{2}-2x$ = $\frac{-11}{28}$
$2x$ = $\frac{9}{2}$-$\frac{-11}{28}$
$2x$ = $ \frac{137}{28}$
$x$ = $ \frac{137}{56}$