Đáp án+Giải thích các bước giải:
`a)`
`(3x-1)^2-(3x+4)(3x-4)=32`
`⇔(3x)^2-2.3x.1+1^2-[(3x)^2-4^2]=32`
`⇔9x^2-6x+1-(9x^2-16)=32`
`⇔9x^2-6x+1-9x^2+16=32`
`⇔-6x+17=32`
`⇔-6x=15`
`⇔x=-15/6`
`⇔x=-5/2`
Vậy `x=-5/2`
`b)`
`(4x+3)^2-(4x-1)(4x+1)=-14`
`⇔(4x)^2+2.4x.3+3^2-[(4x)^2-1]=-14`
`⇔16x^2+24x+9-16x^2+1=-14`
`⇔24x+10=-14`
`⇔24x=-24`
`⇔x=-1`
Vậy `x=-1`