Đáp án:
Giải thích các bước giải:
9) (-0,5x - 2$\frac{1}{2}$ ) : $\frac{4}{3}$ - (-1) = $\frac{1}{3}$
( -$\frac{1}{2}$x - $\frac{5}{2}$) × $\frac{3}{4}$ + 1 = $\frac{1}{3}$
- $\frac{3}{8}$x - $\frac{15}{8}$ = $\frac{1}{3}$ -1
- $\frac{3}{8}$x = -$\frac{2}{3}$ +$\frac{15}{8}$
x = $\frac{29}{24}$ : ( - $\frac{3}{8}$ )
x = -$\frac{29}{9}$
Vậy x=-$\frac{29}{9}$
10) (3x-1)(-$\frac{1}{2}$x+5)=0
TH1: 3x-1=0 => 3x=1 => x=$\frac{1}{3}$
TH2: -$\frac{1}{2}$x+5=0
=>-$\frac{1}{2}$x=-5
=> x = 10
Vậy x thuộc { 10; $\frac{1}{3}$ }
11) $\frac{1}{2}$+$\frac{2}{3}$ : (3x-1) = $\frac{-7}{-6}$
$\frac{2}{3}$ : (3x-1) = $\frac{7}{6}$ - $\frac{1}{2}$
$\frac{2}{3}$ : (3x-1) = $\frac{2}{3}$
3x-1 = $\frac{2}{3}$ : $\frac{2}{3}$
3x-1 = 1
3x = 2
x = $\frac{2}{3}$
Vậy x = $\frac{2}{3}$
