Đáp án :
`c)x=16/5` hoặc `x=14/5`
`b)x=11/5` hoặc `x=(-1)/5`
Giải thích các bước giải :
`c)(x-3)^2=1/25`
`<=>(x-3)^2=(1/5)^2`
`<=>`\(\left[ \begin{array}{l}x-3=\dfrac15\\x-3=\dfrac{-1}5\end{array} \right.\)
`<=>`\(\left[ \begin{array}{l}x=\dfrac15+3\\x=\dfrac{-1}5+3\end{array} \right.\)
`<=>`\(\left[ \begin{array}{l}x=\dfrac15+\dfrac{15}5\\x=\dfrac{-1}5+\dfrac{15}5\end{array} \right.\)
`<=>`\(\left[ \begin{array}{l}x=\dfrac{16}5\\x=\dfrac{14}5\end{array} \right.\)
Vậy : `x=16/5` hoặc `x=14/5`
`b)5/2=3/(|x-1|)`
`<=>5.|x-1|=6`
`<=>|x-1|=6/5`
`<=>`\(\left[ \begin{array}{l}x-1=\dfrac65\\x-1=\dfrac{-6}5\end{array} \right.\)
`<=>`\(\left[ \begin{array}{l}x=\dfrac65+1\\x=\dfrac{-6}5+1\end{array} \right.\)
`<=>`\(\left[ \begin{array}{l}x=\dfrac65+\dfrac55\\x=\dfrac{-6}5+\dfrac55\end{array} \right.\)
`<=>`\(\left[ \begin{array}{l}x=\dfrac{11}5\\x=\dfrac{-1}5\end{array} \right.\)
Vậy : `x=11/5` hoặc `x=(-1)/5`
