Đáp án:
Giải thích các bước giải:
ta có:
⇒6xy-10x+3y-5=7
⇒2x(3y-5)+(3y-5)=7
⇒(3y-5)(2x+1)=7
⇒\(\left[ \begin{array}{l}2x+1=7\\3y-5=1\end{array} \right.\)
\(\left[ \begin{array}{l}2x+1=-7\\3y-5=-1\end{array} \right.\)
⇒\(\left[ \begin{array}{l}2x=6\\3y=6\end{array} \right.\)
\(\left[ \begin{array}{l}2x=-8\\3y=4\end{array} \right.\)
⇒\(\left[ \begin{array}{l}x=3\\y=2\end{array} \right.\)
\(\left[ \begin{array}{l}x=-4\\y=$\frac{4}{3}$ \end{array} \right.\)
