$\begin{array}{l}\dfrac{-4}8=\dfrac x{-10}=\dfrac{-7}y=\dfrac z{-24}\\\Leftrightarrow \dfrac{-1}2=\dfrac x{-10}=\dfrac{-7}y=\dfrac z{-24}\\\text{+ Xét $\dfrac{-1}2=\dfrac x{-10}$}\\\to 2x=-1.(-10)\\\to 2x=10\\\to x=5\\\text{+ Xét $\dfrac{-1}2=\dfrac{-7}y$}\\\to -1y=2.(-7)\\\to -y=-14\\\to y=14\\\text{+ Xét $\dfrac{-1}2=\dfrac z{-24}$}\\\to 2z=(-1).(-24)\\\to 2z=24\\\to z=12\\\text{- Vậy $(x,y,z)=(5,14,12)$} \end{array}$
