Ta có:
$\frac{y}{2}$ -$\frac{9}{x}$ =$\frac{1}{8}$
=>$\frac{xy-18}{2x}$ =$\frac{1}{8}$
=>8(xy-18)=2x
=> 8xy-144=2x
=> 8xy-144-2x=0
=> 2x(4y-1)=144
=> x(4y-1)=72
vì 4y-1 lẻ=> Xảy ra 3 trường hợp:
+)$\left \{ {{x=72} \atop {4y-1=1}} \right.$ =>$\left \{ {{x=72} \atop {y=1/2}} \right.$ (loại)
+)$\left \{ {{x=24} \atop {4y-1=3}} \right.$ =>$\left \{ {{x=24} \atop {y=1}} \right.$ (thoả mãn) +)$\left \{ {{x=8} \atop {4y-1=9}} \right.$ =>$\left \{ {{x=8} \atop {y=2,5}} \right.$ (loại)
Vậy x=24, y=1
