Đáp án:
$y' = e^{2x+1}\left(2\arccos x - 2 - \dfrac{1}{\sqrt{1 - x^2}}\right)$
Giải thích các bước giải:
$\quad y = e^{2x+1}(\arccos x -1)$
$\Rightarrow y' = (\arccos x -1)\left(e^{2x+1}\right)' + e^{2x+1}(\arccos x -1)'$
$\Rightarrow y' = 2(\arccos x -1)e^{2x+1} - e^{2x+1}\cdot \dfrac{1}{\sqrt{1 - x^2}}$
$\Rightarrow y' = e^{2x+1}\left(2\arccos x - 2 - \dfrac{1}{\sqrt{1 - x^2}}\right)$
