`A = -3x(x + 3) - 7 = -3x^2 - 9x - 7`
`= -3(x^2 + 3x) - 7 = -3(x^2 + 3x + 9/4) - 7 + 27/4`
`= -3(x + 3/2)^2 - 1/4 <= -1/4 ∀ x ∈ R`
Dấu ''='' xảy ra `<=> x + 3/2 = 0 <=> x = -3/2`
Vậy `maxA = -1/4 <=> x = -3/2`
``
`B = -2x^2 + 5x - 8 = -2(x^2 - 5/2x) - 8`
`= -2(x^2 - 5/2x + 25/16) - 8 + 25/8`
`= -2(x - 5/2)^2 -39/8 <= -39/8 ∀ x ∈ R`
Dấu ''='' xảy ra `<=> x - 5/2 = 2 <=> x = 5/2`
Vậy `maxB = -39/8 <=> x = 5/2`
``
`C = 3 - x^2 + 4x = -x^2 + 4x + 3 = -(x^2 - 4x) + 3`
`= -(x^2 - 4x + 4) + 3 + 4`
`= -(x - 2)^2 + 7 <= 7 ∀ x ∈ R`
Dấu ''='' xảy ra `<=> x - 2 = 0 <=> x = 2`
Vậy `maxC = 7 <=> x = 2`