Đáp án: $x\in\{-3,-2,1,21,46,-54,-29,-9,-6,-5\}$
Giải thích các bước giải:
Ta có :
$2x^3+11x^2-4x-14=(2x^3+8x^2)+(3x^2+12x)-(16x+64)+50=2x^2(x+4)+3x(x+4)-16(x+4)+50$
$\to 2x^3+11x^2-4x-14\vdots x+4\to x+4\in U(50)=\{1,2,5,25,50,-50,-25,-5,-2,-1\}$
$\to x\in\{-3,-2,1,21,46,-54,-29,-9,-6,-5\}$