Đáp án: `x=3` ;`x=1/6`
Giải thích các bước giải:
` (x-2)(3-x) = (x-3).(5x+1)`
`<=> (x-2)(3-x) - (x-3)(5x+1) =0`
`<=> (x-2)(3-x) + (-1).(x-3)(5x+1)=0`
`<=> (x-2)(3-x) + (3-x)(5x+1)=0`
`<=> (3-x)(x-2+5x+1)=0`
`<=> (3-x)(6x - 1)=0`
`<=>` \(\left[ \begin{array}{l}3-x=0\\6x-1=0\end{array} \right.\)
`<=>` \(\left[ \begin{array}{l}x=3\\x=\dfrac{1}{6}\end{array} \right.\)
Vậy `x=3` hoặc `x=1/6`
