Tìm một nguyên hàm \(F\left( x \right)\) của hàm số \(f\left( x \right) = ax + \dfrac{b}{{{x^2}}}\left( {x \ne 0} \right),\) biết rằng \(F\left( { - 1} \right) = 1,F\left( 1 \right) = 4,f\left( 1 \right) = 0.\)
A.\(F\left( x \right) = \dfrac{{3{x^2}}}{2} + \dfrac{3}{{4x}} - \dfrac{7}{4}.\)
B.\(F\left( x \right) = \dfrac{{3{x^2}}}{2} - \dfrac{3}{{2x}} - \dfrac{7}{4}.\)
C.\(F\left( x \right) = \dfrac{{3{x^2}}}{4} + \dfrac{3}{{2x}} + \dfrac{7}{4}.\)
D.\(F\left( x \right) = \dfrac{{3{x^2}}}{2} - \dfrac{3}{{2x}} - \dfrac{1}{2}.\)
A.\(F\left( x \right) = \dfrac{{3{x^2}}}{2} + \dfrac{3}{{4x}} - \dfrac{7}{4}.\)
B.\(F\left( x \right) = \dfrac{{3{x^2}}}{2} - \dfrac{3}{{2x}} - \dfrac{7}{4}.\)
C.\(F\left( x \right) = \dfrac{{3{x^2}}}{4} + \dfrac{3}{{2x}} + \dfrac{7}{4}.\)
D.\(F\left( x \right) = \dfrac{{3{x^2}}}{2} - \dfrac{3}{{2x}} - \dfrac{1}{2}.\)
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Hóa Học lớp 12
