Đáp án:4 nghiệm
Giải thích các bước giải:
4x (x-1)=l 2x-1 l +1
⇔\(\left[ \begin{array}{l}x=4x^{2}-4x=2x-1+1\\x=4x^{2}-4x=2x+1+1\end{array} \right.\)
⇔\(\left[ \begin{array}{l}x=4x^2-4x-2x=0\\x=4x^2-4x+2x-2=0\end{array} \right.\)
⇔\(\left[ \begin{array}{l}x=4x^2-6x=0\\x=4x^2-2x-2=0\end{array} \right.\)
⇔\(\left[ \begin{array}{l}x=2x(2x-3)=0\\x=2x^2-x-1=0\end{array} \right.\)
⇔\(\left[ \begin{array}{l}x=0\\x=3/2\end{array} \right.\)
\(\left[ \begin{array}{l}x=1\\x=-1/2\end{array} \right.\)
