Đáp án:
Giải thích các bước giải:
Ta có: `3x^2 -3x+y-xy+2=0`
`⇔3x(x-1)+y(1-x)=-2`
`⇔3x(x-1)-y(x-1)=-2`
`⇔(x-1)(3x-y)=-2`
TH1:$\left \{ {{x-1=1} \atop {3x-y=-2}} \right. ⇔\left \{ {{x=2} \atop {y=8}} \right.$
TH2:$\left \{ {{x-1=-1} \atop {3x-y=2}} \right. ⇔\left \{ {{x=0} \atop {y=-2}} \right.$
TH3:$\left \{ {{x-1=2} \atop {3x-y=-1}} \right. ⇔\left \{ {{x=3} \atop {y=10}} \right.$
TH4:$\left \{ {{x-1=-2} \atop {3x-y=1}} \right. ⇔\left \{ {{x=-1} \atop {y=-4}} \right.$
Vậy . . .
