Đáp án:
\(\displaystyle\int\sqrt{3x + 2}dx =\dfrac29(3x+2)\sqrt{3x+2} + C\)
Giải thích các bước giải:
\(\begin{array}{l}
\quad \displaystyle\int f(x)dx = \displaystyle\int\sqrt{3x + 2}dx\\
\to \displaystyle\int f(x)dx = \dfrac13\displaystyle\int\sqrt{3x + 2}d(3x + 2)\\
\to \displaystyle\int f(x)dx = \dfrac13\cdot \dfrac23\sqrt{(3x+2)^3} + C\\
\to\displaystyle\int f(x)dx = \dfrac29(3x+2)\sqrt{3x+2} + C
\end{array}\)
