Đáp án:
`x=7/12` hoặc `x=1/12`
Giải thích các bước giải:
`(x-1/3)^2-1/16=0`
`⇒(x-1/3)^2=1/16`
`⇒(x-1/3)^2=(1/4)^2`
`⇒|x-1/3|=1/4`
\(⇒\left[ \begin{array}{l}x-\dfrac{1}{3}=\dfrac{1}{4}\\x-\dfrac{1}{3}=-\dfrac{1}{4}\end{array} \right.\)
\(⇒\left[ \begin{array}{l}x=\dfrac{1}{3}+\dfrac{1}{4}\\x=-\dfrac{1}{4}+\dfrac{1}{3}\end{array} \right.\)
\(⇒\left[ \begin{array}{l}x=\dfrac{4}{12}+\dfrac{3}{12}\\x=\dfrac{4}{12}-\dfrac{3}{12}\end{array} \right.\)
\(⇒\left[ \begin{array}{l}x=\dfrac{7}{12}\\x=\dfrac{1}{12}\end{array} \right.\)
Vậy `x=7/12` hoặc `x=1/12`
