Lời giải:
Ta có:
$(2x-1) \vdots (x+5)$
Lại có:
$(x+5) \vdots (x+5)$
$=>(2x-1)-(x+5) \vdots (x+5)$
$=>(2x-1)-2(x+5) \vdots (x+5)$
$=> -11 \vdots (x+5)$
$(x+5) ∈ U(-11)$={$-11;-1;1;11$}
$x+5=-11<=>x=-16$
$x+5=-1<=>x=-6$
$x+5=1<=>x=-4$
$x+5=11<=>x=6$
Vậy $x=${$-16;-6;-4;6$}