Đáp án:
Giải thích các bước giải:
`2n-1 \vdots 6-n`
`\to 2n-12+11 \vdots 6-n`
`\to -2(6-n)+11 \vdots 6-n`
Mà `-2(6-n ) \vdots 6-n`
`\to 11 \vdots 6-n`
`\to 6-n \in Ư(11)`
`\to 6-n \in{1,-1,11,-11}`
`\to n\in{5,7,-5,17}`
,
`3n \vdots 5-2n`
`\to 6n \vdots 5-2n`
`\to 6n-15+15 \vdots 5-2n`
`\to -3(5-2n)+15 \vdots 5-2n`
`\to 15 \vdots 5-2n`
`\to 5-2n \in Ư(15)`
`\to 5-2n \in Ư{1,-1,3,-3,5,-5,15,-15}`
`\to 2n\in {4,6,2,8,0,10,-10,20}`
`\to n\in{2,3,1,4,0,5,-5,10}`
