Để $A=(n+3).(n+1)$ là số nguyên tố thì $A$ chỉ có $2$ ước là $1$ và chính nó
Mà $\color{red}{\text{n+3>n+1}}$
⇒ $\color{blue}{\text{n+1=1}}$
⇔ $\color{green}{\text{n=0}}$
$\color{white}{\text{Như.ý<3}}$
Đáp án:
Giải thích các bước giải:
(n+3)(n+1) nto khi 1 trong 2 số bằng 1
Mà n+1 nhỏ hơn => n+1=1
=> n=0
Thử lại (0+3)(0+1)=3nto ( chọn )
Giúp mình với mình đang cần gấp
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giải và biện luận phương trình với tham số m a, m(x-1)=5-(m-1)x b, m(x+m)=x+1 c, m(m-1)x=2m+1 d, m(mx-1)=x+1 M.n giúp mình vs ạ đanh cần gấp
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