Đáp án:
$2^{x+1}$ . $7^{y-1}$ = $98^{x+y}$
<=>2. $2^{x}$ . $7^{y}$/7 = $98^{x}$. $98^{y}$
<=> 2/7 = $(\frac{98}{2})^{x}$ . $(\frac{98}{7})^{y}$
<=> 2/7 = $49^{x}$ . $14^{y}$
<=> 2. $7^{-1}$ = $7^{2x}$ . $7^{y}$. $2^{y}$
<=> 2. $7^{-1}$ = $7^{2x+y}$ . $2^{y}$
=> 2x+y = -1, y = 1 => x = -1