\(x^2+2xy=24\)
\(\Leftrightarrow x\left(x+2y\right)=24\)
\(\Leftrightarrow x,x+2y\inƯ\left(24\right)=\left\{1;24;2;12;3;8;4;6\right\}\)
+) Với \(x=1\)
\(\Leftrightarrow1.\left(1+2y\right)=24\)
\(\Leftrightarrow y=\dfrac{23}{2}\)
+) Với \(x=24\)
\(\Leftrightarrow24\left(24+2y\right)=24\)
\(\Leftrightarrow y=-\dfrac{23}{2}\)
Vân...vân & mây ... mây Bn tự xét tiếp @@
